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Calculate the pH of a 0.30 M solution of NH4Cl. (Kb for NH3 = 1.8 × 10–5

a) 3.33 

b) 4.89 

c) 9.11 

d) 7.00 

e) 11.67 

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2 Answers

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by (68.8k points)

The pH of a 0.30 M solution of NH4Cl is 4.89.

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by (446 points)
NH4^+1 + H2O <--> H3O^+1 + NH3

Ka = [H3O+][NH4]/[NH4+]

Ka = Kw/Kb = 5.6x10^-10

Ka = 5.6x10^-10 = X^2/(0.30-X)

and solving this you will get your pH

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