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The equation of motion of a projectile is y = 12x - (3/4)x^2. Given that g = 10ms^–2 ,

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The equation of motion of a projectile is y = 12x - (3/4)x2. Given that g = 10ms–2 , what is the range of the projectile? 

(a) 12 m 

(b) 16 m 

(c) 30 m 

(d) 36 m

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1 Answer

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Best answer

Correct option (b)

Explanation:

Vs/g = 15m/sec

v(t = 2) = 15 - 10 x 2 = - 5m/sec

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