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A small bead of mass m moving with velocity v gets threaded on a stationary semicircular ring of mass m and radius R kept on a horizontal table.

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A small bead of mass m moving with velocity v gets threaded on a stationary semicircular ring of mass m and radius R kept on a horizontal table. The ring can freely rotate about its centre. The bead comes to rest relative to the ring. What will be the final angular velocity of the system?

(A) v / R 

(B) 2v / R 

(C) v / 2R 

(D) 3v / R

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1 Answer

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Best answer

Correct option: (C) v / 2R

Explanation:

Applying conservation principle of angular momentum,

mvR = (mR2 + mR2 )ω

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