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A closed cylinder is divided into two rooms by a frictionless piston held in place by a pin,  Room A has 10 L air at 100 kPa, 30°C, and room B has 300 L saturated water vapor at 30°C. The pin is pulled, releasing the piston, and both rooms come to equilibrium at 30°C and as the water is compressed it becomes two phase. Considering a control mass of the air and water, determine the work done by the system and the heat transfer to the cylinder.  

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C.V. A + B, control mass of constant total volume.

Energy equation: mA(u2 – u1)A + mB(uB2 – uB1) = 1Q2 1W

Process equation: V = C ⇒ 1W2 = 0

T = C ⇒ (u2 – u1)A = 0 (ideal gas)

The pressure on both sides of the piston must be the same at state 2. Since two-phase:

 

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