It should be noted that VAF stands for the potential of point A with respect to point F. The easiest way of finding it is to start from the reference point F and go to point A along any available path and calculate the algebraic sum of the voltages met on the way. Starting from point F as we go to point A, we come across different battery voltages. Taking the sign convention given in Art. 1.28, we get
(i) VAF = − 24 + 4 + 8 − 6 + 12 = − 6V
The negative sign shows that point A is negative with respect to point F by 6V.
(ii) Similarly, VEA = − 12 + 6 − 8 − 4 = − 18 V
(iii) Starting from point B, we get VFB = 6 − 8 − 4 + 24 = 18V.
Since the result is positive it means that point F is at a higher potential than point B by 18V