Question

A reaction A → B follows a second order kinetics Doubling the concentration of A will increase the rate of formation of B by a factor of : 

(a) 1/4 

(b) 4 

(c) 1/2 

(d) 2

Answer 1

Correct option (b) 4

Explanation:

Rate = k[A]² when concentration is doubled

r = k[(2A)²

= k 4[A]² The new rate become 4 times