Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Physics by (71.9k points)

A rope is stretched between two boats on a lake. A man in the first boat pulls the rope with a constant force of 5 kg-wt. Find the velocity of the boat relative to the shore and relative to the other boat five seconds after the man began pulling the rope. The mass of the first boat with the man is 250kg, the mass of the other boat with its load is 500kg. Neglect the resistance of water. Solve the problem by more than one method.

1 Answer

+1 vote
by (68.7k points)
selected by
 
Best answer

Answer: The velocity of the first boat relative to the shore is 1m/sec. The velocity relative to the second boat is 1.5 m/sec.

Explanation:

Each boat receives an impulse Ft equal to 25kg-wt-sec. As a result, the first boat acquires a velocity v3 = Ft/m1 relative to the shore; the second boat acquires a velocity v2 = Ft/m2 also relative to the shore. The velocity of the first boat relative to the second is v = v3 + v2. If we take g to be approximately 10m/sec2, we obtain v1 = 1m/sec; v2 = 0.5m/sec; and v = 1.5m/sec. The problem may also be solved by applying Newton's second law to obtain the acceleration of the boats and then by making use of the formula relating uniform acceleration to velocity. 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...