Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
8.4k views
in Work, energy and power by (72.0k points)
recategorized by

Sledges slide down an ice-covered hill from a height h (Fig.) and stop after having travelled the distance CB. The distance AB is known to be equal to 5. Determine the coefficient of friction k of the sledges on the icy surface over the run DCB.

1 Answer

+1 vote
by (68.8k points)
selected by
 
Best answer

Answer:

Explanation:

At the top of the hill, the sledges possess a potential energy E equals to mgh. During the motion, this energy is converted into the work A1 in overcoming the force of friction along section DC and into the work A2 in overcoming the force of friction along section CB, i.e., 

E = mgh = A1 + A2.

Since l/S < 1, a1 > 0 and the sledges will move with uniform acceleration along section DC. The acceleration along section CB is a2 = — kg, and the sledges decelerate uniformly. 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...