In the first case the boy does an amount of work
A = 1/2(mv12).
in throwing the stone. If in the second case he throws the stone with the same force, doing the same amount of work, the latter is expended in imparting kinetic energy to the stone and to the boy himself. Therefore
where u is the velocity of the boy. According to the law of conservation of momentum,
Since the power is given by N = Fv and since, in the second case, the stone moves faster relative to the boy than in the first case, (v > v1), the boy should develop a greater power in the second case.