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The abrasive wheel on a grinding machine has a diameter of 60 cm and operates at 120 rev/min. The work piece being ground is pressed against the wheel with a force of 100 kg-wt. What is the power developed by the grinding machine if the coefficient of friction between the wheel and the work piece is 0.2? 

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Answer: N ≅ 1h.p.

Explanation:

The force of friction which must be overcome during the grinding is F1 = kF, where F is the force on the grinding wheel. The velocity v of the circumference of the grinding wheel is πdn, where n is the number of revolutions of the wheel in a second. Hence the required power is 

N = F1v = kFπdn.

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