Dipole moment
p = q × 2l = (3 × 10 –6 ) (2 × 10 –3 )
p = 6 × 10 –9 C-m
(a) Electric field in equatorial position,
Electric potential, V = 0
(b) On rotating the dipole through 90º, the same point now will be in axial position. So, electric field
and electric potential