Question

A parallel-plate capacitor with a plate area S and distance between plates d, is filled with a dielectric of dielectric constant ε in one case and filled with electrolyte of conductivity λ in another. Find the relation between the capacitance in the first case and the conductance in the second case.

Answer 1

Explanation:

The capacitance is given by C = εS/4πd. The resistance of the capacitor after being filled with the electrolyte is R = d/λS, and its conductance G is 1/R = λS/d. Hence C = εG/4πλ.

The above expressions are of a general character, and are valid for any capacitor of any shape and are widely used in electrical calculations.