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A circuit having a resistance of 100Ω is connected to a source of constant voltage. An ammeter with an internal resistance of 1Ω is connected in the circuit to measure the current. What was the current in the circuit before the ammeter was connected if the ammeter reads 5A?

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Answer: I0 = 5.05 amperes.

Explanation:

If the source voltage is V, the current in the circuit before the ammeter is connected is I0 = V/R, and the current after the ammeter is connected is I1 = V/(R + R0). Therefore

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