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in Physics by (67.9k points)

A 5 kg aluminum radiator holds 2 kg of liquid R-134a both at –10°C. The setup is brought indoors and heated with 220 kJ from a heat source at 100°C. Find the total entropy generation for the process assuming the R-134a remains a liquid. 

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C.V. The aluminum radiator and the R-134a.

Energy Eq.  m2u2 – m1u1 = 1Q2 – 0

Process: No change in volume so no work as used above. 

The energy equation now becomes (summing over the mass)

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