Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
7.6k views
in Physics by (67.9k points)

Oxygen gas in a piston cylinder at 300 K, 100 kPa with volume 0.1 m3 is compressed in a reversible adiabatic process to a final temperature of 700 K. Find the final pressure and volume using constant heat capacity

1 Answer

+2 votes
by (63.3k points)
selected by
 
Best answer

C.V. Air. Assume a reversible, adiabatic process.

Energy Eq   u2 - u1 = 0 − 1w2 ;

Entropy Eq s2 - s1 = ∫ dq/T + 1s2 gen = 0/ 

Process: Adiabatic 1q2 = 0

Reversible 1s2 gen = 0

With these two terms zero we have a zero for the entropy change. So this is a constant s (isentropic) expansion process. 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...