C.V. Air in pump. Assume that both cases result in a reversible process.
State 1: P0, T0
State 2: 300 kPa, ?
One piece of information must resolve the ? for a state 2 property.
Case (I) Quickly means no time for heat transfer
Q = 0, so a reversible adiabatic compression.
With constant s and constant heat capacity
Case (II) Slowly, time for heat transfer so T = constant = T0.
The process is then a reversible isothermal compression.
T2 = T0 = 298 K
=> V2 = V1P1/P2 = 8.44 cm3