C.V. Air of constant mass m2 = m1 = m out to ambient.
Thus the unknown is the exponent n.
m = P1V1 /(RT1) = 110 × 0.1/(0.287 × 298.15) = 0.1286 kg
The relation from the process and ideal gas is
From the entropy equation
1S2,gen = m(s2 - s1) - 1Q2/T0
= 0.1286 × (-0.106) + (5.144/298.15) = 0.00362 kJ/K