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+2 votes
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in Mathematics by (57.7k points)
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The value of the integral ∫ log tan x dx x ∈ [0,π ⁄ 2] is equal to :

(a) π/4 

(b) π/2 

(c) 0 

(d) π

2 Answers

+1 vote
by (17.0k points)
selected by
 
Best answer

Correct option is (c) 0

Let, 

\(I = \int \limits_0^\frac \pi 2\log(\tan x)dx\)

Using the property

\(\int \limits_a ^b f(x)dx = \int \limits_a ^bf(a + b- x)dx,\) we get:

\(I = \int \limits _0^\frac \pi 2\log(\tan (\frac \pi 2 - x))dx\)

⇒ \(I = \int\limits_0^\frac \pi 2 \log(\cot x)dx\)

\(= \int \limits_0^\frac \pi 2 \log\frac 1{\tan x}dx\)

\(= - \int \limits_0^\frac \pi 2\log(\tan x)dx\)

\(I = -I\)

⇒ \(I = 0\)

+1 vote
by (71.7k points)

Correct option (c) 0

Explanation:

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