Correct option (c)
Explanation:
Six girls and five boys can sit in a row in 11 ! ways.
∴ exhaustive number of cases = 11 !
Six girls can sit in a row in 6 ! ways and in each such arrangement there are 7 places between them in which 5 boys can be seatd in 7P5 ways.
Therefore, the total number of ways in which no two boys sit together = 6 ! 7P5.
Hence, required probability