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In a bipolar – transistor at room temperature, if the emitter current is doubled, the voltage across its base – emitter junction 

(a) Doubles 

(b) Halves 

(c) Increases by about 20 mV 

(d) Decreases by about 20 mV

1 Answer

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Best answer

Correct option (d) Decreases by about 20 mV

Explanation:

In a BJT emitter current is doubled and one has to find the base emitter voltage, so we consider the p – n junction formed by emitter and base. The junction current is given by

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