The forces acting on different parts are shown in figure. Consider the vertical equilibrium of “the ladder plus the person” system. The forces acting on this system are its weight (80 kg) g and the contact force N + N = 2 N due to the floor. Thus
2 N = (80 kg) g or N = (40 kg) (9.8 m/s2) = 392 N
Next consider the equilibrium of the left leg of the ladder. Taking torques of the forces acting on it about the upper end,
N (2m) tan 30° = T (1m)