C.V. Throttle. Steady state, adiabatic q = 0 and no shaft work w = 0.
Inlet state: hi = 346.8 kJ/kg; si = 1.2792 kJ/kg K
Energy Eq he = hi
Exit state: P = 291 kPa, he = hi
which is two-phase
se = sf + xsfg = 0.5408 + 0.1638 × 4.9265 = 1.3478 kJ/kg K
The reversible work is the difference in availability also equal to the expression in Eq.