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0 votes
43.3k views
in Physics by (106k points)

For an isosceles prism of angle A and refractive index μ, it is found that the angle of minimum deviation δm= A. Which of the following options is/are correct?
(A) For the angle of incidence i1 = A, the ray inside the prism is parallel to the base of the prism
(B) For this prism, the refractive index μ and the angle of prism A are related as A = 1/2 cos -1 (μ/2) 
(C) At minimum deviation, the incident angle i1 and the refracting angle r1 at the first refracting surface are related by r1 = (i1/2)
(D) For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is i1 = sin-1( sinA√(4cos2 A/2 - 1 - 
cosA))

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1 Answer

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by (32.5k points)

(A, C, D)
For minimum deviation (when i1 = A)
i1 = e
r1 = r2 = r (say) = A/2

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