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in Physics by (106k points)

A drop of liquid of radius R = 10–2 m having surface tension S = 0.1/4π Nm-1 divides itself into K identical drops In this process the total change in the surface energy ΔU = 10–3 J. If K = 10α then the value of α is

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Neglecting 1 we get 102 = 10α/3 

α/3 =2,α =6

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