Question

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is

(a) 1/9 

(b) 2/9

(c) 7/9 

(d) 8/9.

Answer 1

(a) : No. of houses = 3 = No. of favourable cases
No. of applicants = 3,
∴ Total number of events = 3³
(because each candidate can apply by 3 ways)
Required probability = 3/3³ = 1/9.