Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
40.9k views
in Mathematics by (150k points)

Solution of the differential equation cosxdy = y(sinx – y)dx, 0 < x < π/2 is
(a) sec x = (tanx + c)y 

(b) y secx = tanx + c

(c) y tanx = secx + c 

(d) tanx = (secx + c)y

1 Answer

0 votes
by (87.2k points)
selected by
 
Best answer

(a) : 1st solution:
cosx dy = y(sin x – y)dx
⇒ cosxdy = ysinxdx – y2dx
⇒ cosxdy – ysinxdx = –y2dx

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...