# solve the following pair of linear equation by substitution method s-t=3,s÷3+t÷2=6

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solve the following pair of linear equation by substitution method s-t=3,s÷3+t÷2=6

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Solution: We have

– = 3 ... (i)
s/3 + t/2 = 6 ... (ii)
From equation (i), we gets t + 3
Putting this value in equation (ii), we get
t+3/3 + t/2 = 6
2t + 6 + 3t = 36
5t = 30
t = 30/5 ... (iv)
Putting in equation (iii), we obtain
s = 9
∴ s = 9, t = 6