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Two vehicles (masses m1 and m2, velocities v1 and v2) crash head-on, see  After a plastic impact the vehicles are entangled and slide with locked wheels a distance s to the right. The coefficient of kinetic friction between the wheels and the road is µ. Calculate v1 if v2 and s are known.

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The total momentum of the system remains unchanged during the collision. We assume that positive velocities are directed to the right (note the direction of v2). We then obtain the velocity ¯v of the vehicles after the impact : 

 In order to relate the distance s to the velocity v  we apply the work-energy theoram

T1-T0=U.

. We insert the kinetic energies

T0 = (m1 + m2)v-2/2, T1=0

 the work of the friction force

U= -RS

and Coulomb's friction law 

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