Given the parabola is y2 = 4x
∴ a = 1
Given line y – 2x + 5 = 0
Slope m = 2
The normal is parallel to the line y – 2x+5 = 0
Slope of the normal = 2
Equation of the normal at ‘t’ is y + tx = 2at + at3
∴ Slope = –t = 2 (⇒t = –2)
Equation of the normal is y-2x =2.1(-2) +1( -2)3-4 -8 = -12
2x – y – 12 = 0.