A two metre long rod is suspended with the help of two wires of equal length. One wire is of steel and its cross-sectional area is 0.1 cm2 and another wire is of brass and its cross-sectional area is 0.2 cm2. If a load W is suspended from the rod and stress produced in both the wires is same then the ratio of tensions in them will be
(a) Will depend on the position of W
(b) T1 / T2 = 2
(c) T1 / T2 = 1
(d) T1 / T2 = 0.5