Given equation of parabola is (y – 0)2 = 8(x – 3)
Which is of the form (y – k)2 = 4a(x – h)
Where 4a = 8 ⇒ a = 2
∴ Vertex = (h, k) = (3, 0)
and focus = (h+a, k) = (3+2, 0) = (5, 0)
Since PQS is an equilateral triangle.
∠SQP = 60° ⇒ ∠SQZ = 30°
Also in ∆ SZQ, we have sin 30° = SZ /SQ
∴ SQ (SZ)/sin 30°=2(SZ) 2(4) 8
Hence length of each side of the triangle is 8.