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0 votes
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in Mathematics by (63.3k points)

∫sin t/t + 1 = α, x∈[0,1] dt  then the value of  ∫sint/2 /4π + 2 -t   x∈[4π - 2 ,4π]  dt  is equal to

(a)  α

(b)  -α

(c)  πα

(d)  2α

1 Answer

+1 vote
by (67.9k points)
selected by
 
Best answer

Correct option  (b) –α

Explanation:

Put 4π – t = 2z in the second integral

= – dt = 2dz

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