Correct option (b) a(a + b + c) > 0
Explanation:
a > 0
ƒ(0) ⇒ c > 0
ƒ(2) > 0 ⇒ a + b + c > 0
aƒ(1) > 0 & cƒ(1) > 0
a(a + b + c) > 0 and c (a + b + c) > 0
a < 0
ƒ(0) < 0 ⇒ c < 0
ƒ(1) < 0 ⇒ a + b + c < 0
aƒ(1) > 0 & c.ƒ(1) > 0
a(a + b + c) > 0 and c (a + b + c) > 0