Correct option (a) (–3, –1) ∪ (3, 5)
Explanation
D > 0
ƒ(–2)ƒ(4) < 0
(–2m)2 –4.1.(m2–1) > 0
(4 + 4m + m2 – 1) (16 – 8m + m2 – 1) < 0
4 > 0 (m2 +4m + 3) (m2 – 8m + 3)
⇒ m ∈ R ......(1)
(m + 1) (m + 3) (m – 3) (m – 5) < 0
⇒ m ∈(–3, –1) ∪ (3, 5) ......(2)
From (1) and (2) , m ∈ (–3, –1) ∪ (3, 5)