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The eccentric angles of the extremities of latus rectum to the ellipse

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The eccentric angles of the extremities of latus rectum to the ellipse x2/a2 + y2/b2 = 1 are given by

(a)  tan-1(±be/a)

(b)  tan-1(±be/a)

(c)  tan-1(±b/ae)

(d)  tan-1(± a/be)

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1 Answer

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Best answer

Correct option (c)  tan-1(±b/ae)

Explanation:

Let L(acosθ , bsinθ) = (± ae, ±b2/a)

acosθ =  ± ae bsinθ = ±b2/a

tanθ =  ±b/ae

θ =  tan-1(b/ae)

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