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0 votes
4.5k views
in Mathematics by (67.9k points)

P is a variable point on the ellipse x2/a2 + y2/b2 = 1 with AA' as the major axis. Then the maximum area of the triangle AP A' is

(a)  ab

(2)  2ab

(c)  ab/2

(d)  None of these

1 Answer

+1 vote
by (63.3k points)
selected by
 
Best answer

Correct option (a) ab

Explanation:

Maximum area corresponds to P when it is at either end of the minor axis and hence area for such a position of P is 1/2 (2a).(b) = ab.

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