Correct option (c) 56m
Explanation:
When particle comes to rest
V = 0 = dx/dt = d/dx(40 + 12t - t3)
⇒ 12 - 3t2 = 0
⇒ t2 = 12/3 = 4 ∴ t = 2sec
Therefore distance travelled by particle before coming to rest,
x = 40 + 12t – t3 = 40 + 12 × 2 – (2)3 = 56m