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in Chemistry by (57.7k points)

A volume of 31.7 cm3 of a 0.1-normal NaOH is required for the neutralization of 0.19 g of an organic acid whose vapour is thirty times as dense as gaseous hydrogen. 

Problem: 1. Give the name and structural formula of the acid. (The acid concerned is a common organic acid.) 

1 Answer

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Best answer

(a) The supposed acid may be: HA, H2A, H3A, etc. 

n(NaOH) = c V = 0.1 mol dm-3 x 0.0317 dm3 = 3.17 × 10-3 mol 

(b) From the ideal gas law we can obtain:  

ρ12 = M1/M2

M(H2) = 2 g mol-1 

M(acid) = 30 x 2 = 60 g mol-1 

By comparing with (1): v = 1 

The acid concerned is a monoprotic acid and its molar mass is 60 g mol-1

The acid is acetic acid: CH3−COOH 

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