Question

The equilibrium constant of the reaction H₂ + I₂ 2HI is at 600°C equal to 70.0 . 

How much iodine (in %) is converted till the equilibrium is reached if the reactants are mixed in: 

(a) 1 : 1 molar ratio at 600°C; 

(b) 2 : 1 molar ratio at 600°C (the amount of hydro gen is twice as great as that of iodine). 

2. How many moles of hydrogen should be mixed with one mole of iodine when 99 % of iodine is to be converted to hydrogen iodide till the equilibrium is reached at 600°C? 

Answer 1

1(a) (two alternative solutions) 

α = 0.807 , i. e. 80.7 % 

1b) (two alternative solutions)