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in Mathematics by (53.3k points)

ABCD is a square of unit side. It is folded along the diagonal AC so that the plane ABC is perpendicular to the plane ACD. The shortest distance between the lines AB & CD is

(a)   √3/2

(b)   3/2

(c)   2/3

(d)  √2/3

1 Answer

+1 vote
by (63.3k points)
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Best answer

Correct option  (d)  √2/3

Explanation:

Let A(1,0,0) B(1,1,0), C(0,1,0), D(0,0,0)

Equation of CD is

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