We will use the nominal-π method to solve the problem. For a length of 150 km :
R = 0.15 × 150 = 22.5 Ω ; X = 0.6 × 150 = 90 Ω ; Y = 150 × 10−5 S = 15 × 10−4 S
Z = (R + j X) = (22.5 + j 90) = 92.8 ∠75º ohm ; Y = 15 × 10−4 ∠90º S
(b) Now, the regulation at the receiving-end is defined as the change in voltage when full-load is thrown off, the sending-end voltage being held constant.
Now, when load is thrown off, IR = 0. Hence, putting this value in VS = AVR + BIR, we get