Question

The number of values of k for which the system of equations (k + 1)x + 8y = 4k, kx + (k + 3)y = 3k – 1 has infinitely many solutions 

(a)   0 

(b)   1 

(c)   2 

(d)   Infinite 

Answer 1

Correct option  (b)  1

Explanation:

k = 1,3

Now put k = 3 ⇒ 4x + 8y = 12, 3x+6y = 8

 x + 2y = 3 ≠ 8/3

No solution

Hence k = 1 gives infinite solutions