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A point object at 15 cm from a concave mirror of radius of curvature 20 cm is made to oscillate along the principal axis with amplitude 2 mm. The amplitude of its image will be :

(A)  2 mm

(B)  4 mm

(C)  8 mm

(D) 16 mm 

1 Answer

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Best answer

Correct option (C) 8 mm

Explanation:

Transverse magnification = mT  = - v/u

Longitudinal magnification = mL =  - dv/du = m2T

here : du = 2mm; u = 15 cm; f = 10 cm; dv = ? 

⇒ dv = 8 mm

∴  Amplitude of image oscillation is 8 mm.

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