Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
8.7k views
in Chemistry by (59.7k points)

0.35 g of an organic substance was Kjeldahlised and the ammonia obtained was passed into 100 ml of N/5 H2SO4. The excess acid required 154 ml of N/10 NaOH for neutralisation. Calculate the percentage of nitrogen in the compound

1 Answer

+1 vote
by (56.9k points)
selected by
 
Best answer

Volume of N/5 H2SO4 solution taken = 100 mL 

The volume of N/5 H2SO4 neutralised by N/10 

NaOH can be obtained as follows :

 

= 77 mL 

Therefore, 

Volume of N/5 H2SO4 used for 

neutralising ammonia = (100 - 77) mL 

 = 23 mL 

Then, 

Percentage of nitrogen in the sample 

= 1.4 x Normality volume of acid

Percentage of nitrogen in the sample 

= 1.4 x 1/5 x 23 / 0.23 = 18.4 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...