Volume of N/5 H2SO4 solution taken = 100 mL
The volume of N/5 H2SO4 neutralised by N/10
NaOH can be obtained as follows :
= 77 mL
Therefore,
Volume of N/5 H2SO4 used for
neutralising ammonia = (100 - 77) mL
= 23 mL
Then,
Percentage of nitrogen in the sample
= 1.4 x Normality volume of acid
Percentage of nitrogen in the sample
= 1.4 x 1/5 x 23 / 0.23 = 18.4