Correct option (A) - I2(R1 + R2)
Explanation:
Given, Zi = ∞
A0L = ∞
Vi0 = 0
V2 = (R1//R2)I1
= R1R2/(R1 + R2)I1 .....(1)
KCL at inverting node
V2/R1 + (V2 - V0)/R2 = 0 (∴ Zi = ∞)
V0/R2 = V2[1/R1 + 1/R2]
V0/R2 = (R1R2/(R1 + R2))I1[(R2 + R1)/R1R2]
⇒ V0 = I1R2