Given x[n] = sin(πn/5); N = 10
⇒ Fourier series co-efficients are also periodic with period N = 10
x[n] = 1/2je(j(2π/10)n)-1/2je(-i(2π/10)n)
a1 = 1/2j; a-1 = - 1/2j ⇒ a-1 = a-1 + 10 = a9 = -1/2j
(a1 = a1 + 10), (a-1 = a-1 + 10)} or a1 = a1 + 20
a-1 = a-1 + 20
⇒ k = 10m + 1 or k = 10m - 1 ⇒ B = 10