Correct option (C) 2(s + 4)
Explanation:
By observing the options, if we place other options, characteristic equation will have 3rd order one, where we cannot describe the settling time.
If C(s) = 2(s + 4) is considered
The characteristic equation, is
s2 + 3s + 2 + 2s + 8 = 0
⇒ s2 + 5s + 10 = 0
Standard character equation s2 + 2ξωns + ωn2 = 0
ω2n = 10; ξωn = 2.5
Given, 2% settling time, 4/ξωn < 2 ⇒ ξωn > 2