Current through 8-Ω resistance =20/8 =2.5 A
This current is divided into two parts at point A; one part going along path AC and the other along path ABC which has a resistance of 28Ω.
l2 = 2.5 x 11/(11 + 28) = 0.7
Hence, ammeter reads 0.7 A.
Resistance between A and C =(28 x 11/39) ohm.
Total circuit resistance = 8 + 11 + (308/39) =1049/39Ω
∴ E = 2.5 x 1049/39=67.3 V