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in Physics by (53.1k points)

As isotropic glass slab of refractive index 1.5 is 30 cm thick. The rear surface of the slab is polished. A point source. S is placed at a distance of 20 cm from the front surface. Calculate the distance between the source and the image formed by reflection and refractions. 

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Since it is given after reflection and refractions. So first reflection, thence, I1 is formed 10 cm behind the mirror which acts as virtual object, now image of this virtual object from slab well be final image. So apparent distance (l1) = nr/ni(30cm + 10 cm)

= 1.5/1 x 40 cm =  60 cm

So distance b/w I1 and S = 30 cm 

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