Question

A piece of copper having a rectangular cross section 15.2 mm x 19.1 mm is pulled in tension with 44,500 N force producing only elastic deformation. Calculate the resulting strain. Given: Y_c = 1.2 × 10¹¹ N/m² .

Answer 1

A = 15.2 x  19.2 mm² = 15.2 × 19.2 x 10^–6 m² ; 

F = 44,500 N

Strain = F/AY = 44500/15 .2 x 19.1 x 10^-6 x 1.2 x 10¹¹

 = 0.001277